Question

Find the 11th term of the A.P. 4, 9, 14, ....​

Answer 1

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Answer 2

Step-by-step explanation:

solution

given

Ap= 4,9,14

first

a= 4

d = 9-4=5

n=11

as we know

$t_{n} = a + (n - 1) \times d$

put all the values we get

$t_{11} = 4 + (11 - 1) \times 5$

$t_{11} = 4 + 10 \times 5$

$= 4 + 50$

$t_{11} = 54$