Find the 11th term of the sequence: 60, 54, 48, 42
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Answer:
11th term is 0
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Given: Some terms of the sequence are = 60,54,48,42
To Find: 11th term of the sequence
Solution:
The following sequence is in an arithmetic sequence
The formula for the nth term in an arithmetic progression is
Tₙ = a + (n-1)d, where Tₙ is the nth term, a is the first term, n is the number of terms, d is the common difference
In this arithmetic progression, a = 60
T₂ = a +(2-1)d
54 = 60 + d
d = 54 - 60
d = -6
For the 11th term
T₁₁ = a + (11-1)d
T₁₁ = 60 + 10(-6)
T₁₁ = 60 + (-60)
T₁₁ = 0
Therefore, the 11th term is 0.
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