find the 12 term of AP 3, 5, 7. . . . . . .
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Given A.P = 3, 5, 7, 9, …. 201
Here, a = 3 and d = (5 – 3) = 2
Now,
find the number of terms when the last term is
known i.e,
201 an
= 3 + (n – 1)2
= 201 3 + 2n – 2
= 201 2n
= 200 n
= 100
Hence, the A.P has 100 terms.
So, the 12th term from the end is same as (100 – 12 + 1)th of the A.P which is the 89th term.
⇒ a89 = 3 + (89 – 1)2
= 3 + 88(2)
= 3 + 176
= 179
Therefore, the 12th term from the end of the A.P is 179.
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