Find the 12 term of series 3a-b,4a,5a+b (A.P)
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Answer:
here your answer...
Step-by-step explanation:
here a=3a-b
and common difference
d=4a-(3a-b)
=4a-3a+b
= a+b
tn=a+(n-1)d
t12=3a-b+(12-1)a+b
=3a-b+11a+11b
=14a+10b is your answer
hope it's will help you
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