Question

Find the 12 term of the AP 14.9, 4.-1.-6...​

Answer 1

$\textbf{AP = 14, 9, 4, -1, -6...}$

a = 14

d = $a_{2}$ - $a_{1}$

=> 9 - 14 = -5

We have first term = 14

And common difference = -5

We have to find the 12th term

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Formula used..

$a_{n}$ = a + (n - 1)d

=> $a_{12}$ = 14 + (12 - 1) (-5)

=> $a_{12}$ = 14 + (11) (-5)

=> $a_{12}$ = 14 - 55

=> $a_{12}$ = -41

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The 12 term of the AP 14,9, 4,-1,-6... is - 41

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