Find the 12 terms of the AP with 1st term and d=10
Answers
Answer:
To find the number of terms in an arithmetic sequence, divide the common difference into the difference between the last and first terms, and then add 1.
Step-by-step explanation:
The general form of an Arithmetic Progression is a, a + d, a + 2d, a + 3d and so on. Thus nth term of an AP series is Tn = a + (n - 1) d, where Tn = nth term and a = first term. Here d = common difference = Tn - Tn-1. The sum of n terms is also equal to the formula where l is the last nth Term of an AP. The nth term of an arithmetic progression whose first term is a1 and whose common difference is d is given by an = a1 + (n – 1) d..
Answer:
Given:
a=10
d=10
therefore the ap is a, a+d,a+2d,.....a+11d
10, 20,30,40,50,60,70,80,90,100,110,120.....
Proof:
a12= a+ 11d
=10 +11(10)
=10+110
=120