Question

find the 12th term from the end of the AP:3,6,9..., 60​

Answer 1

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Step-by-step explanation:

ANSWER ::

First term = a = 3

Common difference = d = 3

So 12th term

= a + (12 - 1)d

= a + 11d

= 3 + 33

= 36

Answer 2

$\bf{\underline{\underline{Question}}}$

$\:$

Find the 12th term from the end of the

AP: 3,6,9...,60 .

$\:$

$\bf{\underline{\underline{Given}}}$

$\:$

$\small\tt{a\:=\:60}$

$\:$

$\small\tt{As\:we\:are\:finding\:from\:the\:end\:of\:term}$

$\tt{so\:,}$

$\:$

$\small\tt{d\:=\:3\:-\:6\:=\:-3}$

$\small\tt{n\:=\:12}$

$\:$

$\bf{\underline{\underline{Solution}}}$

$\:$

$\small\tt{a_{12}\:=\:a\:+\:(12-1)d}$

$\small\tt{a_{12}\:=\:60\:+\:(11)(-3)}$

$\small\tt{a_{12}\:=\:60\:+\:-(33)}$

$\small\tt{a_{12}\:=\:60\:-\:33}$

$\small\tt{\underline{\boxed{a_{12}\:=\:27}}}$

$\:$

$\bf{\underline{\underline{Hope\:It\: Help\:You}}}$