Question

Find the 12th term from the end of the following arithmetic progressions:
(i)3,5,7,9,...201
(ii)3,8,13,...,253
(iii)1,4,7,10,...,88

Answer 1

Answer:

a) here,

a=201 & d= -2

a12= a + 11d

a12= 201 + 11(-2)

a12= 201 - 22

a12= 189

b) here,

a=253 & d=-5

a12= a + 11d

a12= 253 + 11(-5)

a12= 253 - 55

a12= 198

c) here,

a=88 & d=-3

a12= a + 11d

a12= 88 + 11(-3)

a12= 88 - 33

a12= 55

hope it helps

(please forgive mistakes if any)