Find the 12th term from the last of the AP 10,12,....124
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Answer:
126 = 8+(n-1)2
118 = (n-1)2
59 = n-1
n = 60
the pth term from the last
t(n-p+1) = a+(n-p)d
t(60-10+1) = 8 +(60-10)2
t51 = 108
Step-by-step explanation:
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