Find the 12th term from the one of
the AP : -2 -4, -6... -100.
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Given :-
The AP is -2 , -4 , -6 , .......-100
To Find :-
The 12th term of the Ap
Solution :-
Here ,
The First term of the AP is ( a1) = -2
The second term of the AP is ( a2) = -4
so, The common difference is = ( a 2 - a1)
= ( - 4 + 2)
= -2
Now ,
a12 = a + ( n -1 ) d
a12 = -2 + ( 12 - 1 ) -2
a12 = -2 + 11 × ( -2)
a12 = -2 + ( -22 )
a12 = -2 - 22
a12 = - 24
Therefore , The 12th term of the AP is -24 .
Formullas :-
To find the no. of term of the Ap from First we use ,
= a + ( n - 1) d
where ,
a = 1st term .
n = number of the term
d = common difference
To Find the no. of term from the end of the AP we use ,
= l - ( n - 1) d
where,
l = last term
n = no. of term
d = common difference .
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