Find the 12th term of a ap from the end 17,14,11,........,-61
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-28 is the 12 th term of a ap from end ...
explanation ,
-61 is the first term from the end .
therefore a = -61
and common difference = d = 3
therefore ,
using the formula we get ,
tn= a+(n-1 ) d
t12 = -61 +(12-1)3
=-61+11×3
=-61+33
= -28
therefore 12 th term of the AP from end is -28 ..
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