Find the 12th term of a GP, whose 8th term is 192 and the common ratio is 2.
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If a₁ is the first term, a_{n}a
nn is the nth term and r is the common ratio of the given G.P. series then
a_{n}a
n
=a₁rⁿ⁻¹
a₈=a₁×(2)⁸⁻¹=192
or, a₁×2⁷=192
or, a₁=192/2⁷
or, a₁=2⁶×3/2⁷
or, a₁=3/2
∴, a₁₂=a₁r¹²⁻¹
=3/2×(2)¹¹
=3×(2)¹⁰
=3×1024
=3072
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