Question

find the 12th term of an ap 6,1,-4​

Answer 1

Answer:

-49

Step-by-step explanation:

In an AP, the $n^{th}$ term, $t_{n}$ is given by:

$t_{n}$ = a + (n-1)d, where a is the first term and d is the common difference between two consecutive terms.

Here, a = 6 and d = 1 - 6 = (-4) - 1 = -5

We are asked to find the $12^{th}$ term, $t_{12}$.

$t_{12}$ = a+(n-1)d = 6 + (12-1)(-5) = 6 + (-55) = -49