find the 12th term of AP whose 10th term and 16th terms are 39 and 63 . find the sum of first 20 terms
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the answer is 47 . hope you like the answer
Step-by-step explanation:
a 10 = 39
a+ 9d = 39 _ (¡)
a 16 = 63
a + 15d =63 _ (¡¡)
(i) - (ii)
a +9d =39
- a +15d = 63
- - -
- 6d = -24
d = 4
in (¡) , a + 9 × 4 = 39
a = 3
a 12 = a + 11d
= 3 + 11 × 4 = 47
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