find the 12th term of gp whose 8th term 192 and common is 2
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Answered by
10
Given common ratio(r) = 2
8th term of an GP = 192
=> ar^7 = 192 => a(2^7) = 192
=> a(128) = 192 => a = 3/2
∴ 12th term of an GP = ar^11 = 3/2 (2^11) = 3072
Answered by
3
Answer:
Given that 8th term of a GP is 192
And common ratio is 2
if a is 1st term and r is common Ratio then we know that tn=ar power (n-1)
Here tn=192 and r=2 and n=8
so a=192/128=3/2
Now 12th term will be
tn=(3/2)*2 to the power 11
answer will be 2472
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