Question

Find the 12th term of gp. Whose 8th term is 192 and the common ratio is 2

Answer 1

here is ur answer bacha

hope its clear to you

Answer 2

Answer:

The required 12th term of the GP is 3072.

Step-by-step explanation:

It is given that the common ratio between the terms is 2.

Also, 8th term of the GP is 192.

Let the first term of the GP be a,

From the properties of geometric progressions,

= > nth term = a x r^( n - 1 ), where a is the first term, r is the common ratio and n is the number of terms.

Therefore,

= > 8th term = 192

= > a x r^( 8 - 1 ) = 192

= > a x 2^( 8 - 1 ) = 192

= > a x 2^7 = 192

= > a = ( 192 / 2^7 )       ...( i )

Hence,

12th term of the GP should be = a x r^( 12 - 1 )

= > 12th term of the GP = ( 192 / 2^7 ) x ( 2^11 )

= > 12th term of the GP = 192 x 2^( 11 - 7 )

= > 12th term of the GP = 192 x 2^4

= > 12th term of the GP = 192 x 16

= > 12th term of the GP = 3072

Hence the required 12th term of the GP is 3072.