Find the 12th term of on 16,11,6 ....?
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Answered by
1
Answer: -39
Step-by-step explanation:
AP= 16,11,6.....
a=16
d=-5
n=12
a'n= a+(n-1)d
a12= 16+(12-1)-5 = 16+(11)-5
a12=16-55 = -39
Answered by
0
Answer:
12th term of an series =-39
common difference d= -5
a= 16
Step-by-step explanation:
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