Find the 12th term of the AP: 14,9,4,-1.
Answers
Answered by
2
Step-by-step explanation:
The nth term of the AP is given by
Tn = a + (n - 1)d
= 14 + (n - 1) (-5) = (19 - 5n) ...[ a = 14 and d = -5].
Therefore,nth term = (19 - 5n).
12th term of the given AP is
T12 = a + (12-1) d = (a + 11d)
= 14 +11 (-5) = -41 [ a = 14 and d = -5].
Therefore, 12th term = -41.
Answered by
4
Answer:
-41
Step-by-step explanation:
given:-
In AP,
First term(a) = 14
common difference (d) = 9-14 = -5
n = 12
12 th term = t12
By the AP formula,
tn = a+(n-1)d
=> t12 = 14+(12-1)×(-5)
=> t12 = 14+11×-5
=> t12 = 14-55
=> t12 = -41
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