Question

find the 12th term of the AP 14, 9, 4, -1, -6​

Answer 1

Step-by-step explanation:

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Answer 2

$\mathtt{ \huge{ \fbox{SOLUTION :}}}$

Given ,

First term = 14

Common difference (d) = 9 - 14 = -5

We know that , the nth term of an AP is given by

$\sf \large \fbox{a_{n} = a + (n - 1)d}$

Substitute the n = 12 in above the formula , we get

$\sf \mapsto a_{12} = 14 + (12 - 1)( - 5) \\ \\\sf \mapsto a_{12} = 14 + 11( - 5) \\ \\\sf \mapsto a_{12} = 14 - 55 \\ \\\sf \mapsto a_{12} = - 41$

Hence , 12th term of the given AP is -41