Question

Find the 12th term of the AP: 5,8,11 , 14 ,....
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Answer 1

Answer:

t1 = 5, t2= 8, t3 = 11, t4 = 14

d= 8–5 = 3 a= 5

Step-by-step explanation:

t12 = a+(n–1) d

= 5 + ( 12–1 ) 3

= 5+(11) 3

= 5+ (33)

= 38

Therefore t12 = 38