Find the 12th term of the arithmetic sequence whose common difference is d=8 and whose first term is a1=3.
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Answered by
1
Answer:
12th term be 91.
Step-by-step explanation:
a12 = a + 11d
= 3 + 88
= 91
Answered by
9
Answer:
Question
✳️Find the 12th term of the arithmetic sequence whose common difference is d=8 and whose first term is a1=3.
Solution ⬇️
✍️Here, t1=a1=3 : d=8 ...(given)
✍️to find:12th term of an AP
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✍️Formula ⬇️
✍️An=a+(n-1)d
✍️a12 = 3+(12-1)8
✍️a12=3+11 x 8
✍️a12 = 3+88
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|✍️a12 = 91 |
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Extra formulae
✳️Refer to the attachment
Step-by-step explanation:
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