Question

find the 12th term of this series 4,8,12,16​

Answer 1

Answer:

a = 4

d = 8-4 = 4

n = 12

a12 = a + (n-1)d

= 4 + (12-1)4

= 4 + 11 × 4

= 4 + 44

a12 = 48

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Answer 2

Answer:

12th term is 48

Step-by-step explanation:

First term, A1=4

Common difference, d =8-4=4

n =12

Using formula

$An = A1 + (n - 1) d \\ = 4 + (12 - 1)4 \\ = 4 + 11 \times 4 \\ = 4 + 44 \\ = 48$