Find the 12th terms of the seri
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Answer:
The given series is 4,6,8,10,...
The series is in AP with a=4,d=2
a
n
=
2
n
(2a+(n−1)d)
a
12
=
2
12
(2(4)+(12−1)2)
a
12
=6(8+22)
6×30=180
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