Question

find the 13 term of A.P. -5,-10,-15,-20​

Answer 1

Answer:

-65

Step-by-step explanation:

This is Arithmetic progression. This means there are the first term and Common difference.

$\sf a \: = - 5 \\ a_2 \: = - 10 \\ a_3= - 15$

Clearly the common difference is

$\sf a_2 - a = a_3 - a_2 = -5$

$\sf \: So, \: \: a_{13}= a + 12d \\ \sf \: = - 5 + 12( - 5) \\ \sf = - 5 - 60 \\ = \sf - 65$

Therefore our required answer is -65

Answer 2

Step-by-step explanation:

a=−5a2​
=−10a3​
=−15​

Clearly the common difference is

So,a13​=a+12d
=−5+12(−5)
=−5−60=−65​

Therefore our required answer is -65