Question

find the 13 terms of the Arithmetic progression 4,1,_2,_5..​

Answer 1

Answer:

a13= -44

Step-by-step explanation:

a=4 d=-3

an= a + (n-1)d

putting values we get

AP: -8, -11, -14, -17, -20, -23, -26, -29, -32, -35, -38, -41, -44 and so on.

Answer 2

series= 4,1,-2,-5

13th term=?

n=13, d= a1-a= 4-1 = -3

a13= a+(n-1)d

a13= 4+(13-1)(-3)

=4+(12)(-3)

=4+(-36)

= -32