Question

find the 13th term of an AP -1,-5,-9,-13,,,,,,​

Answer 1

Answer:

It is your answer

Explanation:

This pattern is written in the format in which there is a gap of 3 between each digits.So according to this, the 13th term of this pattern is -48

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Answer 2

Answer:

a13 = -49

Explanation:

We know that,

an = a+(n-1)d

Here,

First term,. a = -1

Common diffrence, d = a2 - a1

= -5 - (-1)

= -5 + 1

= -4

n = 13

Now putting these values in the equation we have,

a13 = (-1) + (13-1)(-4)

-----> a13 = (-1) + (12)(-4)

-----> a13 = (-1) + (-48)

-----> a13 = -49.

So, 13ty term of the given AP (Arithmetic Progression) is (-49).

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