Find the 13th term of geometric sequence 4,-16,64,...
Answers
Step-by-step explanation:
GP= 4 ,-16 , 64 ....
first term of the given GP ( a) = 4
common ratio (r)= T 2 / T 1
= -16/ 4 = -4
T 13 = a r ^ n-1
= 4 × (-4)^ (13-1)
= 4× (-16777216)
= - 67108864
Answer:
The 13th term of the geometric sequence 4,-16,64,... is 67108864.
Step-by-step explanation:
To find the 13th term of the geometric sequence, we need to first find the common ratio (r) between any two consecutive terms. We can do this by dividing the second term by the first term:
r = (-16) / 4 = -4
Now we can use the formula to find the nth term of a geometric sequence:
an = a1 * r^(n-1)
where a1 is the first term, r is the common ratio, and n is the term we want to find.
Substituting the given values, we get:
a13 = 4 * (-4)^(13-1)
a13 = 4 * (-4)^12
a13 = 4 * 16777216
a13 = 67108864
Therefore, the 13th term of the geometric sequence 4,-16,64,... is 67108864.
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