Question

find the 13th term of th A P 4,1,_2_5.....​

Answer 1

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Answer 2

The 13th term of the A P$(a_{13} )$ = - 32

Step-by-step explanation:

The given AP are:

4, 1, - 2, - 5, .....

Here, first term (a) = 4, common difference(d) = 1 - 4 = - 3 and n =13

To find, the 13th term of the A P$(a_{13} )$ = ?

We know that,

The nth term of an AP.

$a_{n} =a+(n-1)d$

∴ The 13th term of an AP.

$a_{13} =4+(13-1)(-3)$

⇒ $a_{13} =4+(12)(-3)$

⇒ $a_{13} =4-36=-32$

Thus, the 13th term of the A P$(a_{13} )$ = - 32