Question

find the 13th term of the Arithmetic progression 4,1,-2,-5......​

Answer 1

Answer:

Given,

a=4 , d=1-4

=-3

13 th term= a+(n-1)

=4+(13-1)

=4+12

=16

hope it helps you

Answer 2

Answer:

Step-by-step explanation:

series= 4,1,-2,-5

13th term=?

n=13, d= a1-a= 4-1 = -3

a13= a+(n-1)d

a13= 4+(13-1)(-3)

=4+(12)(-3)

=4+(-36)

= -32

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