Question

Find the 13th term of the arithmetic sequence 3x -11, -6, -3x -1, -6x + 4.

Answer 1

Answer:

Please refer to the above attachment..

Thank you.

Answer 2

The 13th term of sequence is -33x + 49

Given:

3x -11, -6, -3x -1, -6x + 4 is a Arithmetic sequence

To find:

13th term of the Arithmetic sequence

Solution:

From given data 3x -11, -6, -3x -1, -6x + 4 is a Arithmetic sequence

Here first term a = 3x - 11

Common difference d = term 2 - term 1 = -6 - (3x -11)  = -6 - 3x+11 = -3x +5

As we know nth term of a sequence a$_{n}$ = a +(n-1)d

⇒ 13 th term a₁₃ =  a + (13-1)d = a + 12d  

⇒ a + 12d  =  3x - 11 + 12(-3x +5)

= 3x -11 - 36x + 60

= - 33x + 49  

Therefore, 13th term of sequence = -33x + 49

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