Find the 13th term of the arithmetic sequence
x-1, -4x+4, -9x+9
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Step-by-step explanation:
first term a = x-1
common difference d = term 2 - term 1
d= (-4x+4)-(x-1) = -4x+4-x+1 = -5x+5
n=13
13tg term = a+(n-1)d
= x-1+(13-1)(-5x+5)
= x-1+12(-5x+5)
= x-1-60x+60
= -59x+59
therefore 13th term is -59x+59
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