Question

Find the 13th term of the arithmetic sequence
x-1, -4x+4, -9x+9

Answer 1

Step-by-step explanation:

first term a = x-1

common difference d = term 2 - term 1

d= (-4x+4)-(x-1) = -4x+4-x+1 = -5x+5

n=13

13tg term = a+(n-1)d

= x-1+(13-1)(-5x+5)

= x-1+12(-5x+5)

= x-1-60x+60

= -59x+59

therefore 13th term is -59x+59