Question

find the 13th term of the arthemetic progression 4,1,-2,-5​

Answer 1

Answer:

a13 = -32

Step-by-step explanation:

a = 4

d = a1 - a2 = 1-4 = -3

a13 = a+12d = 4+12x(-3) = 4-36 = -32

I hope its help u

Answer 2

Step-by-step explanation:

a=4 d=-3

a+(13-1) d

4+12×-3

4-36=-32