Question

Find the 13th term of the geometric sequence 5, 10, 20, ...

Answer 1

Answer:

20,480

Step-by-step explanation:

a= first term = 5

r = 2

To find : 13th term

a13 = a(r^13-1)

a13=5(2^12)

=20,480

The 13th term of this geometric progression = 20,480

Answer 2

Sequence :

5, 10, 20, ....

First term is 5

Common Difference is 5

$a_{13} = a + 12d = 65$