Math, asked by anuragsoniboss8, 5 days ago

find the 143rd term in the sequence 3,9,15,21​

Answers

Answered by rahulkumar9521
0

Answer:

861

Step-by-step explanation:

it is the correct answer

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Answered by tennetiraj86
10

Step-by-step explanation:

Given:-

The sequence 3,9,15,21,...

To find:-

Find the 143rd term?

Solution:-

Given sequence is 3,9,15,21,...

First term = 3

Common difference = d =

9-3 = 6

15-9 = 6

21-15 = 6

Since the common difference is same throughout the sequence,They are in the AP

We have

First term = a = 3

Common difference = d = 6

We know that

The general or nth term of an AP

an = a+(n-1) d

now , 143rd term

=> a143 = 3+(143-1)(6)

=> a143 = 3+(142)(6)

=> a 143 = 3+852

=> a143 = 855

Answer:-

The 143rd term of the given sequence is 855

Used formula:-

  • The general or nth term of an AP
  • an = a+(n-1) d

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