Math, asked by Anonymous, 10 months ago

Find the 14th term from the end of the Arithmetic Progression
11,18,25,.......,221.​

Answers

Answered by kuldeep20941
0

Answer:

=>130

Step-by-step explanation:

See The Attachment My Friend....

Attachments:
Answered by BrainlyConqueror0901
4

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{14th\:term\:from\:the\:end=130}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given :}} \\ \tt: \implies A.P= 11,18,25,....,221 \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies 14th \: term \: form \: the \: end = ?

• According to given question :

 \tt \circ \: First \: term = 221 \\ \\ \tt \circ \: Common \: difference = -7\\ \\ \tt \circ \: n = 14 \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies a_{n} = a + (n - 1)d \\ \\ \tt: \implies a_{14} = 221+ (14 - 1) \times - 7\\ \\ \tt: \implies a_{14} =221+ 13 \times - 7 \\ \\ \tt: \implies a_{14} =221- 91 \\ \\ \green{\tt: \implies a_{14} =130} \\ \\ \green{\tt \therefore 14th \: term \: from \: the \: end \: is \: 130}

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