Question

Find the 14th term of

${( {2}^{10} - {2}^{7} x) }^{ \frac{13}{2} }$


❌❌NO SPAMMING❌❌​

Answer 1

Hii bro,

I hope this answer helps you

plzzz tell me in COMMENTS that answer is RIGHT /WRONG

✔/❌

Answer 2

Solution:-

=> ( 2^10 - 2^7 x) ^13/2

=> ( 2^10 - 128x)^13/2

=> √ (2^10 - 128 x)^13

=> √ (2^10 - 128 x)^12 × √( 2^10 - 128x)

=> √( 2^10 - 128x)^12 × √( 2^10 - 128x)

=> ( 1024 - 128x)^6 × √2^10-128x

=> ( 1024 - 128x)^6 × √(1024 - 128x)

=> ( 1024 - 128x)^6 × 2^3 √( 16-2x)

=> (1024 - 128x)^6 × 8√( 16-2x)

=> 8√(16-2x) × (1024 - 128x)^6

Hence,

8√(16-2x) × (1024 - 128x)^6