Find the 14th term of the sequence 7, 8, 9, 10, ….
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Here the given sequence is in the form of A.P.
The common difference d = 1.
So, from the formula for finding the nth term of A.P.
tn = a + (n-1)d
Here we need to find the 14 th term so,
n = 14,
a is the first term of the sequence a = 7.
d is the common difference d = 1
Subdtituting the known values in the formula,
t14 = 7 + (14 - 1) 1
t14 = 7 + 13
t14 = 20.
So the 14 th term of the sequence is 20.
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