Find the 15", 24" and n" term (general term) of an A.P. given by 3, 15,
27, 39,..
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15th term =
24th term =
nth term (general term) = a + (n-1)d
We already know that nth term is a + (n-1)d where a is the first term in the A.P and d being the common difference between the terms.
According to the question,
a = 3
d = 12
So applying the general term formula we get
When n = 15,
= a + (n-1)d
= 3 + (15-1)12
= 3 + (14)12
= 3 + 168
= 171
When n = 24
= a + (n-1)d
= 3 + (24-1)12
= 3 + (23)12
= 3 + 276
= 279
So the 15th term of this A.P is 171 and the 24th term of this A.P is 279.
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1
It is the answer for the sum
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