Question

find the 15 term of an ap with second term 11 and common difference 9​

Answer 1

Answer:

15th term is 130

Step-by-step explanation:

Given:-

a2=11

d=9

since, a2=d+a1

then, a1=a2-d

a1=11-9

a1=2

Now,

aN=2a+(N-1) d

N=15

a15=2(2) +(15-1) 9

a15=4+(14) 9

a15=4+126

a15=130

therefore, 15th term is 130

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Answer 2

Answer:

130

Step-by-step explanation:

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