Find the 15 term of the A.P with second term 11 and common difference 9
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Answer:
The Value OF 15 Term is 128
Step-by-step explanation:
Given :- a2 = 11
D = 9
According To The Formula:-
→ an = a + (n-1) d
→ a2 = a + (2-1) 9
→ 11 = a + 9
→ a = 11 - 9
→ a = 2
→ an = a + (n-1) d
→ a15 = 2 + ( 15 -1 ) 9
→ a15 = 2 + 126
→ a15 = 128
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