find the 15 term of the sequence 3,10,17
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3,10,17,...
since, 10-3 = 17-10.... they are in A.P.
common difference (d) = 10-3 = 7
first term (a) = 3
nth term (n) = 15
then,
15th term = a + (n-1)d = 3 + (15-1)7 = 3 + (14)7 = 3 + 98 = 101
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