find the 15th of the series 1,4,7,10... what will be the sum of 18 terms?
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Answer:
GIVEN:- A=1 , D=3
TO FIND:- T15 AND S18
SOL:-
Tn = a + (n-1) d [formula]
T15 = 1 + (15-1) 3
T15 = 1 + 14 × 3
T15 = 1 + 42
T15 = 43
NOW,
Sn = n/2 [2a + (n-1) d ] {formula}
S18 = 18/2 [ 2×1 + (18-1) 3]
S18 = 9 [2+ 17 × 3]
S18 = 9 [2+51]
S18 = 9 × 53
S18 = 477
ANS:- THEREFORE,THE 15TH TERM ON THE SERIES IS 43 AND SUM OF 18 TERMS IS 477
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