Question

find the 15th term from the end of A.p 3,8,13, 253​

Answer 1

Answer:

73 is your answer

Step-by-step explanation:

formula of A.p. is

tn=a+(n-1)d

here a=1st term

n =no.of term

d=difference between second term from 1st term

so,

a=3

n=15

d=8-3

=5

Now put variable in the above formula

t15=3+(15-1)5

=3+(14)5

= 3+70

=73

73 is 15th term of this series

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Answer 2

Answer:

The 15th term is 183.

Step-by-step explanation:

An arithmetic progression (AP) is a list or sequence of integers in which each phrase is obtained by adding a specified number to the previous term.

The given sequence is 3,8,13......253

First term (a)=3

Last term $t_n$=253

Difference (d) =$8-3=5$

Now,

$t_n=a+(n-1)d$

$253=3+(n-1)5$

$253-3=(n-1)5$

$250\div5=(n-1)$

$n=51 terms$

In 51 terms , 15th terms from the last term will be-

$51-15+1=52-15$

$=37th$

$t_37=a+(37-1)d\\=3+36\times5\\=183$

The 15th term is 183.

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