Find the 15th term from the last of the A.P. 5, 12, 19, ........... 250.
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first term a= 5
common difference d = 12-5= 7
last term an= 250
no of terms n
using formula
an = a+(n-1)×d
250 = 5 +( n-1)×7
245= 7n -7
252=7n
n= 252/7 = 36
15 last term will be 36 -15 = 21 from starting
so
15th term from last = 21 term from begining
21st term = a+20d. = 5 + 20× 7
= 5 + 140 = 145
hence 15th term from the last of the AP is 145
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