Find the 15th term from the series 2,5,8, 11, …
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here first term is 2
common difference is 3
using formula. Tn = a+(n-1)×d
where n is number of term
we get
T15=2+(15-1)×3
=2+42
=44
Hence the 15th term is 44
common difference is 3
using formula. Tn = a+(n-1)×d
where n is number of term
we get
T15=2+(15-1)×3
=2+42
=44
Hence the 15th term is 44
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