Find the 15th term of A.P. whose 7th term is 82 and 11th term is 62.
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Step-by-step explanation:
let consider 1st term = a
common difference = d
according to question,
a +6d = 82-----------------(1)
a +10d = 62-----------------(2)
from equation 1 & 2
a = 112
d= -5
so,
15th term = a + 14d
= 112 + 14× (-5)
= 42
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