Question

Find the 15th term of an AP x-7, x-2, x+3,......

Answer 1

hope this helps u ....

Answer 2

Answer:

The 15th term is (x+63)

Step-by-step explanation:

Given the A.P series

$x-7, x-2, x+3,......$

we have to find the 15th term of A.P

An arithmetic sequence is a sequence of numbers where each number is the sum of previous number and a constant, called the common difference.

$\text{Common difference=}d=x-2-(x-7)=x-2-x+7=5$

$x-7, x-2, x+3,......$

a=x-7, d=5, n=15

The recursive formula for A.P is

$a_n=a+(n-1)d$

$a_{15}=x-7+(15-1)5$

$a_{15}=x-7+70$

$a_{15}=x+63$

Hence, the 15th term is (x+63)