Question

find the 15th term of ap √2,3√2,3√2,7√2.....​

Answer 1

Answer:

29√2

Step-by-step explanation:

an = a + (n-1) × d

here , a = √2 , n = 15 , d = 3√2 - √2 = 2√2

an = √2 + (15 - 1) × 2√2

=> √2 + 28√2

=> 29√2

so, the 15th term is 29√2....