Question

Find the 15th term of AP 3,7,11,15

Answer 1

Answer:

15th term: 59

Step-by-step explanation:

1st term(a) = 3

Common difference =4

$a_{15}= a+14d\\a_{15}= 3+14*4\\a_{15}= 3+56 = 59\\\\or\\\\a_{15}= a+(n-1)d\\a_{15}= 3+(15-1)4\\a_{15}=3+14*4\\a_{15}= 3+56= 59$