find the 15th term of given A. P. 2,4,6,8,10
Answers
Answered by
4
Answer:30,240
Step-by-step explanation:
Let a be the first term and d the common difference
a=2
d=4-2=2
So, 15th term= a+(15-1)*d
=2+(14*2)
=2+28
=30
Sum of first 15 terms = n/2(a+an), where n= number of terms
=15/2(2+30)
=15/2(32)
=15*16
=240
SAMiTUP:
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Answered by
1
Here is your Answer dear:
2,4,6,8,10..........
a=2
d=2
a15=a+14d
=2+14*2
=2+28
15th term of ap =30
Sum of n terms=n/2(2a+(n-1)d))
Sum of 15 terms=15/2(4+14*2)
=15/2(32)
=240
Regards
Sahil2dracula
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